Integrand size = 21, antiderivative size = 110 \[ \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx=-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}-\frac {4 \cos (a+b x)}{5 b d^3 \sqrt {d \tan (a+b x)}}-\frac {4 \cos (a+b x) E\left (\left .a-\frac {\pi }{4}+b x\right |2\right ) \sqrt {d \tan (a+b x)}}{5 b d^4 \sqrt {\sin (2 a+2 b x)}} \]
-4/5*cos(b*x+a)/b/d^3/(d*tan(b*x+a))^(1/2)+4/5*cos(b*x+a)*(sin(a+1/4*Pi+b* x)^2)^(1/2)/sin(a+1/4*Pi+b*x)*EllipticE(cos(a+1/4*Pi+b*x),2^(1/2))*(d*tan( b*x+a))^(1/2)/b/d^4/sin(2*b*x+2*a)^(1/2)-2/5*sec(b*x+a)/b/d/(d*tan(b*x+a)) ^(5/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 1.99 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.94 \[ \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx=-\frac {2 \left (4 \operatorname {Hypergeometric2F1}\left (\frac {3}{4},\frac {3}{2},\frac {7}{4},-\tan ^2(a+b x)\right ) \sec ^2(a+b x)+3 \left (-2+\csc ^2(a+b x)+\csc ^4(a+b x)\right ) \sqrt {\sec ^2(a+b x)}\right ) \sin (a+b x) \sqrt {d \tan (a+b x)}}{15 b d^4 \sqrt {\sec ^2(a+b x)}} \]
(-2*(4*Hypergeometric2F1[3/4, 3/2, 7/4, -Tan[a + b*x]^2]*Sec[a + b*x]^2 + 3*(-2 + Csc[a + b*x]^2 + Csc[a + b*x]^4)*Sqrt[Sec[a + b*x]^2])*Sin[a + b*x ]*Sqrt[d*Tan[a + b*x]])/(15*b*d^4*Sqrt[Sec[a + b*x]^2])
Time = 0.59 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.04, number of steps used = 10, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.476, Rules used = {3042, 3088, 3042, 3088, 3042, 3095, 3042, 3052, 3042, 3119}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {\sec (a+b x)^3}{(d \tan (a+b x))^{7/2}}dx\) |
\(\Big \downarrow \) 3088 |
\(\displaystyle \frac {2 \int \frac {\sec (a+b x)}{(d \tan (a+b x))^{3/2}}dx}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {2 \int \frac {\sec (a+b x)}{(d \tan (a+b x))^{3/2}}dx}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3088 |
\(\displaystyle \frac {2 \left (-\frac {2 \int \cos (a+b x) \sqrt {d \tan (a+b x)}dx}{d^2}-\frac {2 \cos (a+b x)}{b d \sqrt {d \tan (a+b x)}}\right )}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {2 \left (-\frac {2 \int \frac {\sqrt {d \tan (a+b x)}}{\sec (a+b x)}dx}{d^2}-\frac {2 \cos (a+b x)}{b d \sqrt {d \tan (a+b x)}}\right )}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3095 |
\(\displaystyle \frac {2 \left (-\frac {2 \sqrt {\cos (a+b x)} \sqrt {d \tan (a+b x)} \int \sqrt {\cos (a+b x)} \sqrt {\sin (a+b x)}dx}{d^2 \sqrt {\sin (a+b x)}}-\frac {2 \cos (a+b x)}{b d \sqrt {d \tan (a+b x)}}\right )}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {2 \left (-\frac {2 \sqrt {\cos (a+b x)} \sqrt {d \tan (a+b x)} \int \sqrt {\cos (a+b x)} \sqrt {\sin (a+b x)}dx}{d^2 \sqrt {\sin (a+b x)}}-\frac {2 \cos (a+b x)}{b d \sqrt {d \tan (a+b x)}}\right )}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3052 |
\(\displaystyle \frac {2 \left (-\frac {2 \cos (a+b x) \sqrt {d \tan (a+b x)} \int \sqrt {\sin (2 a+2 b x)}dx}{d^2 \sqrt {\sin (2 a+2 b x)}}-\frac {2 \cos (a+b x)}{b d \sqrt {d \tan (a+b x)}}\right )}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {2 \left (-\frac {2 \cos (a+b x) \sqrt {d \tan (a+b x)} \int \sqrt {\sin (2 a+2 b x)}dx}{d^2 \sqrt {\sin (2 a+2 b x)}}-\frac {2 \cos (a+b x)}{b d \sqrt {d \tan (a+b x)}}\right )}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
\(\Big \downarrow \) 3119 |
\(\displaystyle \frac {2 \left (-\frac {2 \cos (a+b x) E\left (\left .a+b x-\frac {\pi }{4}\right |2\right ) \sqrt {d \tan (a+b x)}}{b d^2 \sqrt {\sin (2 a+2 b x)}}-\frac {2 \cos (a+b x)}{b d \sqrt {d \tan (a+b x)}}\right )}{5 d^2}-\frac {2 \sec (a+b x)}{5 b d (d \tan (a+b x))^{5/2}}\) |
(-2*Sec[a + b*x])/(5*b*d*(d*Tan[a + b*x])^(5/2)) + (2*((-2*Cos[a + b*x])/( b*d*Sqrt[d*Tan[a + b*x]]) - (2*Cos[a + b*x]*EllipticE[a - Pi/4 + b*x, 2]*S qrt[d*Tan[a + b*x]])/(b*d^2*Sqrt[Sin[2*a + 2*b*x]])))/(5*d^2)
3.3.70.3.1 Defintions of rubi rules used
Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(b_.)]*Sqrt[(a_.)*sin[(e_.) + (f_.)*(x_)]] , x_Symbol] :> Simp[Sqrt[a*Sin[e + f*x]]*(Sqrt[b*Cos[e + f*x]]/Sqrt[Sin[2*e + 2*f*x]]) Int[Sqrt[Sin[2*e + 2*f*x]], x], x] /; FreeQ[{a, b, e, f}, x]
Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^( n_), x_Symbol] :> Simp[a^2*(a*Sec[e + f*x])^(m - 2)*((b*Tan[e + f*x])^(n + 1)/(b*f*(n + 1))), x] - Simp[a^2*((m - 2)/(b^2*(n + 1))) Int[(a*Sec[e + f *x])^(m - 2)*(b*Tan[e + f*x])^(n + 2), x], x] /; FreeQ[{a, b, e, f}, x] && LtQ[n, -1] && (GtQ[m, 1] || (EqQ[m, 1] && EqQ[n, -3/2])) && IntegersQ[2*m, 2*n]
Int[Sqrt[(b_.)*tan[(e_.) + (f_.)*(x_)]]/sec[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[Sqrt[Cos[e + f*x]]*(Sqrt[b*Tan[e + f*x]]/Sqrt[Sin[e + f*x]]) Int[ Sqrt[Cos[e + f*x]]*Sqrt[Sin[e + f*x]], x], x] /; FreeQ[{b, e, f}, x]
Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)* (c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
Leaf count of result is larger than twice the leaf count of optimal. \(371\) vs. \(2(121)=242\).
Time = 1.28 (sec) , antiderivative size = 372, normalized size of antiderivative = 3.38
method | result | size |
default | \(-\frac {\left (-4 \sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}\, \sqrt {-\csc \left (b x +a \right )+1+\cot \left (b x +a \right )}\, \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )}\, E\left (\sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}, \frac {\sqrt {2}}{2}\right )+2 \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )}\, \sqrt {-\csc \left (b x +a \right )+1+\cot \left (b x +a \right )}\, \sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}\, F\left (\sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}, \frac {\sqrt {2}}{2}\right )-4 \sec \left (b x +a \right ) \sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}\, \sqrt {-\csc \left (b x +a \right )+1+\cot \left (b x +a \right )}\, \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )}\, E\left (\sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}, \frac {\sqrt {2}}{2}\right )+2 \sec \left (b x +a \right ) \sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}\, \sqrt {-\csc \left (b x +a \right )+1+\cot \left (b x +a \right )}\, \sqrt {\cot \left (b x +a \right )-\csc \left (b x +a \right )}\, F\left (\sqrt {1+\csc \left (b x +a \right )-\cot \left (b x +a \right )}, \frac {\sqrt {2}}{2}\right )+2 \sqrt {2}+\cot \left (b x +a \right ) \csc \left (b x +a \right ) \sqrt {2}\right ) \sqrt {2}}{5 b \,d^{3} \sqrt {d \tan \left (b x +a \right )}}\) | \(372\) |
-1/5/b/d^3/(d*tan(b*x+a))^(1/2)*(-4*(1+csc(b*x+a)-cot(b*x+a))^(1/2)*(-csc( b*x+a)+1+cot(b*x+a))^(1/2)*(cot(b*x+a)-csc(b*x+a))^(1/2)*EllipticE((1+csc( b*x+a)-cot(b*x+a))^(1/2),1/2*2^(1/2))+2*(cot(b*x+a)-csc(b*x+a))^(1/2)*(-cs c(b*x+a)+1+cot(b*x+a))^(1/2)*(1+csc(b*x+a)-cot(b*x+a))^(1/2)*EllipticF((1+ csc(b*x+a)-cot(b*x+a))^(1/2),1/2*2^(1/2))-4*sec(b*x+a)*(1+csc(b*x+a)-cot(b *x+a))^(1/2)*(-csc(b*x+a)+1+cot(b*x+a))^(1/2)*(cot(b*x+a)-csc(b*x+a))^(1/2 )*EllipticE((1+csc(b*x+a)-cot(b*x+a))^(1/2),1/2*2^(1/2))+2*sec(b*x+a)*(1+c sc(b*x+a)-cot(b*x+a))^(1/2)*(-csc(b*x+a)+1+cot(b*x+a))^(1/2)*(cot(b*x+a)-c sc(b*x+a))^(1/2)*EllipticF((1+csc(b*x+a)-cot(b*x+a))^(1/2),1/2*2^(1/2))+2* 2^(1/2)+cot(b*x+a)*csc(b*x+a)*2^(1/2))*2^(1/2)
Result contains complex when optimal does not.
Time = 0.10 (sec) , antiderivative size = 241, normalized size of antiderivative = 2.19 \[ \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx=-\frac {2 \, {\left ({\left (i \, \cos \left (b x + a\right )^{2} - i\right )} \sqrt {i \, d} E(\arcsin \left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right )\,|\,-1) \sin \left (b x + a\right ) + {\left (-i \, \cos \left (b x + a\right )^{2} + i\right )} \sqrt {-i \, d} E(\arcsin \left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right )\,|\,-1) \sin \left (b x + a\right ) + {\left (-i \, \cos \left (b x + a\right )^{2} + i\right )} \sqrt {i \, d} F(\arcsin \left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right )\,|\,-1) \sin \left (b x + a\right ) + {\left (i \, \cos \left (b x + a\right )^{2} - i\right )} \sqrt {-i \, d} F(\arcsin \left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right )\,|\,-1) \sin \left (b x + a\right ) + {\left (2 \, \cos \left (b x + a\right )^{4} - 3 \, \cos \left (b x + a\right )^{2}\right )} \sqrt {\frac {d \sin \left (b x + a\right )}{\cos \left (b x + a\right )}}\right )}}{5 \, {\left (b d^{4} \cos \left (b x + a\right )^{2} - b d^{4}\right )} \sin \left (b x + a\right )} \]
-2/5*((I*cos(b*x + a)^2 - I)*sqrt(I*d)*elliptic_e(arcsin(cos(b*x + a) + I* sin(b*x + a)), -1)*sin(b*x + a) + (-I*cos(b*x + a)^2 + I)*sqrt(-I*d)*ellip tic_e(arcsin(cos(b*x + a) - I*sin(b*x + a)), -1)*sin(b*x + a) + (-I*cos(b* x + a)^2 + I)*sqrt(I*d)*elliptic_f(arcsin(cos(b*x + a) + I*sin(b*x + a)), -1)*sin(b*x + a) + (I*cos(b*x + a)^2 - I)*sqrt(-I*d)*elliptic_f(arcsin(cos (b*x + a) - I*sin(b*x + a)), -1)*sin(b*x + a) + (2*cos(b*x + a)^4 - 3*cos( b*x + a)^2)*sqrt(d*sin(b*x + a)/cos(b*x + a)))/((b*d^4*cos(b*x + a)^2 - b* d^4)*sin(b*x + a))
\[ \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx=\int \frac {\sec ^{3}{\left (a + b x \right )}}{\left (d \tan {\left (a + b x \right )}\right )^{\frac {7}{2}}}\, dx \]
\[ \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx=\int { \frac {\sec \left (b x + a\right )^{3}}{\left (d \tan \left (b x + a\right )\right )^{\frac {7}{2}}} \,d x } \]
\[ \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx=\int { \frac {\sec \left (b x + a\right )^{3}}{\left (d \tan \left (b x + a\right )\right )^{\frac {7}{2}}} \,d x } \]
Timed out. \[ \int \frac {\sec ^3(a+b x)}{(d \tan (a+b x))^{7/2}} \, dx=\int \frac {1}{{\cos \left (a+b\,x\right )}^3\,{\left (d\,\mathrm {tan}\left (a+b\,x\right )\right )}^{7/2}} \,d x \]